In these solutions, those moves that were required are given in bold type. All else is given for the sake of completeness and for the interest of solvers. Threats are given in parentheses. All problems carry 5 points, distributed as indicated with the solutions.
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1) Joel Fridlizius 4th Prize, Sporten, 1893 Mate in 2 |
1.Sc3! (2.Se6#) (5) 1...Kxc3 2.Sb3# 1...bxc5 2.Qg7# 1...Qxc3 2.Qd6# 1...Qxb5 2.Sxb5# 1...Sxc3 2.e3# 1...Bxe2 2.Sxe2# 1...Bb3 2.Sxb3# |
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2) Josef Holzman Sachove listy, 1900 Mate in 3 |
1.exd5! (1)
(2.Sc6 & 3.b4#) (1)
1...Kxd4 2.Qxd3+ Kc5 3.Sa6# (1)
1...Kxb4 2.Sd2+ Kc5 3.Sb3# (1)
Ka5 3.Sb3#
1...Rxd5 2.Sa6+ Kxd4 3.Qg4# (1)
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3) Franz Pachl & Hermann Weissauer 4th Prize, Sachsische Zeitung, 2004 Mate in 3 |
1.g6! (1)
(2.Sf6+ Kxf5 3.Bd7#) (1)
1...Bxf4 2.Re5+ Bxe5+ 3.Qxe5# (1)
1...Rxe3 2.Bd3+ Rxd3 3.Qxd3# (1)
1...Qxf4 2.Qg2+ Qf3 3.Qxf3# (1)
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4) Valentin F Rudenko 3rd Place, Dniepropetrovsk - Thessaloniki, 2004-2005 Mate in 4 |
1.Qh3? 1...Bf8!
1.Qh5! (1)
(2.Sf4+ exf4 3.Qd5+ Kxe3 4.Qd2# (½)
Bd4 4.Qxd4#
Kxe3 3.Sd5+ Kd3 4.Qxf3#) (½)
1...Be2 2.Qf5 & 3.Rd4+ exd4 4.e5# (1)
1...Se2 2.Qxf3 & 3.Sf4+ Sxf4 4.exf4# (1)
exf4 4.exf4#
1...Sc3 2.Rxc3+ Kxe4 3.Qg4+ Kxd5 4.Rc5# (½)
1...Sxb4 2.Sxb4+ Kxe3 3.Sd5+ Kd3 4.Qxf3# (½)
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5) Enrico Paoli 54 Studi Scacchistici (1947-1957), 1959 White to play and win |
1.h7 (i) (½) 1...Be5+ 2.d4! (ii) (1) 2...Bxd4+ 3.Ka2 (1) 3...Nc3+ 4.Kb3! (1) 4...Nd5 (iii) 5.Kc4 (1) 5...Ke4 6.f3+ 1-0 (½)
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6) Mikhail Marandiuk 3rd Prize, Chepizhni-70 JT, 2004 Selfmate in 3 |
1.Rg4! (1)
(2.Se3+ Qxe3 3.Qe6+ Qxe6#) (1)
1...Bg1 2.Bd3+ Qxd3 3.Qd5+ Qxd5# (1)
1...Qxa4 2.Rxf4+ Bxf4 3.Qxb5+ Qxb5# (1)
1...Bxg4 2.Rxb4+ Qxb4 3.Qc5+ Qxc5# (1)
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7) Camillo Gamnitzer feenschach, 2005 Selfmate in 4 |
1.Bc8? 1...fxe2! or 1...bxa3!
1.Be4? 1...a1=Q+!
1.Bd5? 1...Bxg5!
1.Ba8! (1)
(2.Qd7+ Kxc5 3.Qc6+ Kd4 4.Sxf3+ Sxf3#) (1)
1...fxe2 2.Bf3 (3.Sc6+ Kc4 4.Bxe2+ Sd3#) (1)
Bxg5 3.Se4+ Kd5 4.Sxg5+ Sxf3# (1)
1...bxa3 2.Rg4+ hxg4 3.Qa4+ Kxc5 4.Sd3+ Sxd3# (1)
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8) Rupert J Wood feenschach, 2005 Helpmate in 6: 2 solutions |
1.h5 Kg5 2.Rb1 Kf6 3.g1=R Kxf7 4.Rg7+ Ke8 5.Rc7 Sf7 6.Rb8 Sd6# (2½) 1.Kd8 Kg4 2.g1=Q+ Kf5 3.Qg4+ Kf6 4.Qc8 Ke5 5.Re1+ Kd6 6.Re8 Sxf7# (2½) This problem was previously used in the 2006-2007 Postal Round, a fact mentioned by just one solver. I wonder how many others noticed? I clearly hadn't added the 2006-2007 problems to my list of used problems, but that lapse has now been corrected. |
