MESON Chess Problem Database

Problem Display
PID: 26657 (br1n4/BkP2n2/p1R5/3R4/K7/8/8/8 w - - 0 1)

Bettmann, Henry Wald

Good Companions, 1923

br1n4/BkP2n2/p1R5/3R4/K7/8/8/8

#2

5 + 6

2988 Izbrannie Kompozitsi 1985
5454 Near Snap 2011

SOLUTION

  • SOUND
  • Sets
    • 1...Kc8
      • 2.cxb8Q#
      • 2.cxb8R#
  • Tries
    • 1.Rb6+?
      • 1...Kxa7
        • 2.cxb8Q#
      • 1...Kc8
        • 2.cxb8Q#
      • 1...Kxc7!
    • 1.c8Q+?
      • 1...Kxa7
        • 2.Rxa6#
        • 2.Qxa6#
      • 1...Rxc8!
  • Keys
    • 1.Rd7!
      • threat
        • 2.cxb8S#
        • 2.cxd8S#
        • 2.c8Q#
        • 2.c8R#
      • 1...Kxc6
        • 2.cxb8S#
      • 1...Kxa7
        • 2.c8S#
      • 1...Kc8
        • 2.cxd8Q#
        • 2.cxd8R#
      • 1...Sxc6
        • 2.cxb8Q#
        • 2.cxb8R#
      • 1...Rc8
        • 2.cxd8S#
      • 1...Se5
        • 2.cxd8S#
        • 2.c8Q#
      • 1...Sg5
        • 2.cxb8S#
        • 2.cxd8S#
        • 2.c8Q#
        • 2.c8R#
      • 1...Sd6
        • 2.cxb8S#
        • 2.cxd8S#
        • 2.c8Q#
        • 2.c8R#
      • 1...Sh6
        • 2.cxb8S#
        • 2.cxd8S#
        • 2.c8Q#
        • 2.c8R#
      • 1...Sh8
        • 2.cxb8S#
        • 2.cxd8S#
        • 2.c8Q#
        • 2.c8R#
      • 1...Se6
        • 2.c8Q#
      • 1...a5
        • 2.cxb8S#
        • 2.cxd8S#
        • 2.c8Q#
        • 2.c8R#

This anticipates 51544(1963), 3195(1972)

This is a version of 22009

FEATURES

  • Static
    • TYPE = THREAT
    • CHANGED MATES = 0
    • ADDED MATES = 4
    • REMOVED MATES = 0
  • Sets
    • K(b);S_FLIGHT::PXR(e)=Q
  • Tries
    • Try
      • R(C);CHECK
      • Vars
        • K(b);P-FLIGHT,XB(D)::PXR(e)=Q
        • K(b);S_FLIGHT::PXR(e)=Q
      • Refutation
        • K(b);P-FLIGHT,XP(E)
    • Try
      • P(E);CHECK
      • Refutation
        • R(e);XQ(E)
  • Actual
    • R(B);
    • Threat
      • DUALS(4)
    • Vars
      • K(b);S_FLIGHT,XR(C)::PXR(e)=S
      • K(b);P-FLIGHT,XB(D)::P=S
      • K(b);S_FLIGHT::PXS(f)=Q
      • S(f);SBLOCK,XR(C)::PXR(e)=Q
      • R(e);::PXS(f)=S
      • S(f);::P=Q
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