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Chess Problem 1990b8f501

BDS

feenschach, 1990

1K6/1Pp5/6*3q1/2r1Bk2/3*3S*3bP2/2*3r1pP2/2P5/8

H#2
2 solutions
LEO g6
PAO c3
VAO e4
MAO d4

1.PAd3 MAb3 2.VAxc2 MAd4#
1.Rc6  MAb5 2.VAxb7 MAd4#

If e4 were empty, Black would be mated in the diagram position. So, in each solution, the play involves unpinning the bVA and allowing it to move to a square from which it cannot return to e4, following which the wMA returns to d4.

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