MESON Chess Problem Database

Problem Display
PID: 6156 (8/4kP1R/8/2P1NKP1/8/8/8/8 w - - 0 1)

Szentgyorgy, Erno

Magyar Sakkvilag, 1927

8/4kP1R/8/2P1NKP1/8/8/8/8

#2

6 + 1

273 Mat Plus 1995

SOLUTION

  • SOUND
  • Sets
    • 1...Kd8
      • 2.f8Q#
      • 2.f8R#
    • 1...Kf8
      • 2.Sg6#
  • Tries
    • 1.Kf4?
      • 1...Kd8
        • 2.f8Q#
        • 2.f8R#
      • 1...Kf8
        • 2.Sg6#
      • 1...Ke6!
    • 1.Kg4?
      • 1...Kd8
        • 2.f8Q#
        • 2.f8R#
      • 1...Kf8
        • 2.Sg6#
      • 1...Ke6!
    • 1.Sg6+?
      • 1...Kd8
        • 2.f8Q#
        • 2.f8R#
      • 1...Kd7!
    • 1.Rg7?
      • 1...Kd8
        • 2.f8Q#
        • 2.f8R#
      • 1...Kf8!
    • 1.c6?
      • 1...Kd8
        • 2.f8Q#
        • 2.f8R#
      • 1...Kf8
        • 2.Sg6#
      • 1...Kd6!
    • 1.g6?
      • 1...Kd8
        • 2.f8Q#
        • 2.f8R#
      • 1...Kf8!
  • Keys
    • 1.Ke4!
      • 1...Ke6
        • 2.f8S#
      • 1...Kd8
        • 2.f8Q#
        • 2.f8R#
      • 1...Kf8
        • 2.Sg6#

FEATURES

  • Static
    • TYPE = WAITER
    • CHANGED MATES = 0
    • ADDED MATES = 1
    • REMOVED MATES = 0
  • Sets
    • K(a);S_FLIGHT::P=Q
    • K(a);S_FLIGHT::S(B)
  • Tries
    • Try
      • K(C);P-FLIGHT
      • Vars
        • K(a);S_FLIGHT::P=Q
        • K(a);S_FLIGHT::S(B)
      • Refutation
        • K(a);P-FLIGHT
    • Try
      • K(C);S_FLIGHT
      • Vars
        • K(a);S_FLIGHT::P=Q
        • K(a);S_FLIGHT::S(B)
      • Refutation
        • K(a);P-FLIGHT
    • Try
      • S(B);CHECK
      • Vars
        • K(a);S_FLIGHT::P=Q
      • Refutation
        • K(a);P-FLIGHT
    • Try
      • R(F);
      • Vars
        • K(a);S_FLIGHT::P=Q
      • Refutation
        • K(a);S_FLIGHT
    • Try
      • P(A);
      • Vars
        • K(a);S_FLIGHT::P=Q
        • K(a);S_FLIGHT::S(B)
      • Refutation
        • K(a);S_FLIGHT
    • Try
      • P(D);
      • Vars
        • K(a);S_FLIGHT::P=Q
      • Refutation
        • K(a);S_FLIGHT
  • Actual
    • K(C);S_FLIGHT
    • Vars
      • K(a);P-FLIGHT::P=S
      • K(a);S_FLIGHT::P=Q
      • K(a);S_FLIGHT::S(B)
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